3m^2-29m-10=0

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Solution for 3m^2-29m-10=0 equation:



3m^2-29m-10=0
a = 3; b = -29; c = -10;
Δ = b2-4ac
Δ = -292-4·3·(-10)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-31}{2*3}=\frac{-2}{6} =-1/3 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+31}{2*3}=\frac{60}{6} =10 $

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